How do you solve 2^x=27? - Socratic
2016年11月13日 · Explanation: To solve this problem we need the inverse operation of exponents: logarithms. If 2 raised to some power x is equal to 27, then the logarithm of base 2 and an argument of 27 is equal to x. The answer is log_2 (27) To solve this problem we need the inverse operation of exponents: logarithms. If 2 raised to some power x is equal to 27 ...
How do you factor x^2 - 27? - Socratic
2015年2月1日 · 1 Answer. Anas H. · Massimiliano. Feb 1, 2015. x² −27 = (x)² −(3√3)² = (x +3√3)(x − 3√3) Answer link.
How do you solve 3(x - 1)^2= 27? - Socratic
2018年6月21日 · Answer link. x = 10 3 (x-1)^2 = 27 First, divide both sides by color (blue)3: (3 (x-1)^2)/color (blue)3 = 27/color (blue)3 (x-1)^2 = 9 Now square root both sides: sqrt ( (x-1)^2) = sqrt9 x - 1 = \pm3 Finally, add color (blue)1 to both sides: x - 1 quadcolor (blue) (+quad1) = \pm3 quadcolor (blue) (+quad1) Therefore, x = 4 or -2 Hope this helps!
How do you solve 3^(x-2)=27? - Socratic
2015年5月23日 · 3x−2 = 27. 27 can be written as 33. x − 2 = 3. x = 5 is the solution for the expression. 3^ (x-2)=27 27 can be written as 3^3 3^ (x-2)=3^3 at this stage exponents can be equated x-2 = 3 color (blue) ( x = 5 is the solution for the expression.
How do you solve x^(3/2) = 27? - Socratic
2016年6月29日 · Explanation: Given Eqn. : x3 2 = 27. ∴ {x3 2}2 = 272. ∴ x3 2⋅2 = (33)2. ∴ x3 = 33⋅2 = 36 = (32)3. As powers are same, so must be the bases, so, x = 32 = 9. It can be easily verified that the root found satisfies the given eqn. Hence, the Soln. is x = 9. Answer link.
How do you write 9^(3/2) = 27 in log form? - Socratic
1 Answer. Bill K. Jun 16, 2015. log9(27) = 3 2. Explanation: For b> 0, b ≠ 1 and y> 0, the symbol x = logb(y) represents the unique real number such that bx = y (it's the unique solution of that equation). Since x = 3 2 is the unique solution of the equation 9x = …
How do you solve y^3 - 27 = 9y^2 - 27y? - Socratic
Feb 12, 2017. y = 3. Explanation: y3 − 27 = 9y2 −27y => subtract 9y2 from both sides: y3 − 9y2 −27 = − 27y => add 27y to both sides: y3 − 9y2 +27y −27 = 0 => factor by grouping: y3 − 27− 9y2 + 27y = 0 => difference of two cubes: (y −3)(y2 + 3y + 9) −9y(y −3) = 0 =>factor y − 3: (y −3)(y2 + 3y + 9 − 9y) = 0 => simplify:
What are the vertices and foci of the ellipse 9x^2-18x+4y^2=27?
2017年1月22日 · The vertices are (3,0), (-1,0), (1,3), (1,-3) The foci are (1,sqrt5) and (1,-sqrt5) Let's rearrange the equation by completing the squares 9x^2-18x+4y^2=27 9(x^2-2x+1)+4y^2=27+9 9(x-1)^2+4y^2=36 Dividing by 36 (x-1)^2/4+y^2/9=1 (x-1)^2/2^2+y^2/3^2=1 This is the equation of an ellipse with a vertical major axis Comparing this equation to (x …
How do you factor x^3 - 9x^2 +27x - 27? | Socratic
(x-3)^3 x^3-9x^2+27x-27 =x^3-27-9x^2+27x =(x-3)(x^2+3x+9)-9x(x-3) =(x-3)*(x^2+3x+9-9x) =(x-3)*(x^2-6x+9) =(x-3)*(x-3)^2 =(x-3)^3
How do you write 4x^2-24x+27 in the form of a(x-b)^2+c?
2017年9月8日 · =4(x - 3)^2 - 9 4 x^2 - 24 x + 27 = 4(x^2 - 6 x) + 27 = 4(x - 6/2)^2 - 4(6/2)^2 + 27 = 4(x - 3)^2 - 4(3)^2 + 27 = 4(x - 3)^2 - 36 + 27 =4(x - 3)^2 - 9