Why is the chemical formula for vinegar CH3COOH what it is?
网页2017年2月12日 — CH3COOH is an accepted and common form of writing the structure of acetic acid (commonly known as vinegar when diluted in water). You are right in saying the formal notation should be used - which is C2H4O2 - since it gives the reader the types of atoms and their quantities, and these two characteristics define the exact composition of …
How to create a buffer using CH3COOH and CH3COONa that has …
网页2019年5月23日 — I need to create a buffer using $\ce{CH3COOH}$ and $\ce{CH3COONa}$ that has a pH of exactly $3.75$.. A $\pu{50 mL}$ sample of your buffered solution will have to be able to withstand the addition of $\pu{25.0 …
pH of CH3COOH + HCl solution (shouldn't be a buffer)
网页2019年4月27日 — 0.05 L of a solution containing 0.3 M acetic acid (CHX3COOH, Ka = 1.8 ⋅ 10 − 5) are added to 75 mL of a solution containing 0.02 M hydrochloric acid (HCl, a strong acid). Calculate the pH. Can I simply find the [HX +] released by the reaction of CHX3COOH with water and add them to the [HX +] released by HCl, add the two concentrations and ...
How to create a buffer solution from NaOH and CH₃COOH?
网页2014年7月12日 — 0. In my chemistry book, they say that an approach to making a buffer solution of pH = 5.09 p H = 5.09 is by adding an appropriate amount of strong base (0.052 mol NaOH) (0.052 m o l N a O H) to 0.300 l 0.300 l of 0.025 mol/l CHX3COOH 0.025 m o l / l C H X 3 C O O H. But, I haven’t been able to figure out how they got those numbers.
Why is the boiling point of CH3COOH higher than that of C2H5OH?
网页2015年12月30日 — Consider the alcohol. Here the carbon bearing the $\ce{-OH}$ group is the only polarizing group present. But for $\ce{CH3COOH}$ , the carbonyl carbon is polarized by an $\ce{-OH}$ group as well an $\ce{=O}$ group attached to it, thus increasing its effective polarization more than the alcohol. …
Are CH₃COOH and HCOOCH₃ same? - Chemistry Stack Exchange
网页2020年12月30日 — $\begingroup$ $\ce{CH3COOH}$ is an acid called acetic acid or ethanoic acid. This is the main constituent of vinegar. $\ce{HCOOCH3}$ is a rarely written formula for a volatil liquid called methyl formate, boiling at 31.5°C, which has a not too disagreeable odor and can be synthesized in the lab. $\endgroup$
Can CH3COOH be written as C2H4O2? - Chemistry Stack Exchange
网页2016年9月12日 — Yes you can, if you like being misunderstood. There are several CX2HX4OX2 C X 2 H X 4 O X 2 's, but only one CHX3COOH C H X 3 C O O H. What you absolutely can't do is getting you uppercase/lowercase letters wrong. In chemistry, like in some programming languages, this is considered a major infraction. – Ivan Neretin.
physical chemistry - How is the dissolution of acetic acid that …
网页2014年12月24日 — When acetic acid is dissolved in water there is an equilibrium reaction: $$\ce{CH3COOH + H2O <=> CH3COO- + H3O+}$$ Since acetic acid is a weak acid, the equilibrium position lies well to the left, with only a small fraction of the acetic acid molecules reacting to form ethanoate and hydronium ions.
Solved Construct the expression for Ka for the weak acid ... - Chegg
网页There are 2 steps to solve this one. Construct the expression for Ka for the weak acid, CH3COOH. CH3COOH (aq) + H2O (l) = H3O+ (aq) + CH3COO- (aq) 1 Based on the definition of Ka, drag the tiles into the numerator or denominator to construct the expression for the given acid.
How to find the pH of acetic acid after adding sodium hydroxide?
网页2016年7月1日 — Setting up the equilibrium equation: Kh = Products Reactants, I get (where Kh = Kw / Ka, Ka = 1.8 ⋅ 10 − 5): Kh = (x)(1 ⋅ 10 − 2 + x) x − 1 ⋅ 10 − 2 = 5.55 ⋅ 10 − 10. Which yields [OHX −] = x = 1.11 ⋅ 10 − 9 and so pH = 5.04 which is wrong. I know the answer should be around 12 from the answer sheet. What am I doing wrong?
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