How Do Submarines Dispose of Waste Heat? - Physics Forums
2017年1月27日 · Submarine waste heat disposal works by using a heat exchanger to transfer the heat from the submarine's systems to the surrounding water. The heat exchanger typically consists of a series of tubes that allow the water to flow through, absorbing the excess heat from the submarine. The cooled water is then released back into the ocean.
Calculating Water Evaporation in a Power Plant with Waste Heat Loss
gsxrK3. May 30, 2007. Power. In summary, the conversation revolves around calculating the amount of water evaporated per day in an 800-MW electric power plant with an efficiency of 30%. The solution involves using equations to find the waste heat, latent heat of water, and ultimately determining that 71,363.72 tons of water are evaporated per day.
An 800 MW electric power plant - Physics Forums
2008年7月27日 · An 800 MW electric power plant typically works by using a turbine to convert the energy from a heat source (such as burning coal, natural gas, or nuclear reactions) into mechanical energy. The mechanical energy is then used to turn a generator, which produces electricity. The electricity is then sent to a transformer to increase the voltage for ...
Finding the Exhaust Temperature of a Carnot Engine - Physics …
2010年8月28日 · A Carnot engine performs work at the rate of 360 kW while using 720 kcal of heat per second.If the temperature of the heat source is 650 C, at what temperature is the waste heat exhausted? Homework Equations because Th,Qh,and W are given so i going to use this formula W=Qh*[1-Tc/Th) The Attempt at a Solution
One of the waste products of many nuclear power plants is heat
2005年5月12日 · 6,751. ohwilleke said: One of the waste products of many nuclear power plants is heat. They send it towers in the form of steam . . . No, not quite. What one sees from the cooling tower is 'water vapor' from the sprayers in the tower, which is typical of many non-nuclear cooling towers. The cooling tower, or river, cools the water from the ...
Heat recovery from car radiator. - Physics Forums
2006年11月28日 · The ratio of heat lost from the garage over heat given to the garage is. 3000* (50-20) / 400* (250-50) = 1.12. and when you add the heat lost by opening up the garage door to pull in, your vehicle is an overall drain on the household heating budget. You do even worse by inefficiently draining the heat from the radiator.
What Is the Maximum Efficiency of a Heat Engine Using Lake …
2006年12月6日 · In summary, the maximum possible efficiency of a heat engine using surface lake water at 18.5°C as a heat source and rejecting waste heat to water 0.100 km below the surface at 4.3°C can be calculated using the formula e=1-Qc/Qh, where Qc is the heat absorbed from the "hot" reservoir and Qh is the heat delivered to the "cold" reservoir.
Thermodynamics: Violating Clausius => Violating Kelvin - Physics …
2024年9月25日 · 3) The overall effect is that we have converted 60J of heat from the hot reservoir to 60J of work. There is no waste heat transferred to the low temperature reservoir. Therefore the efficiency of the system is 100%, violating Kelvin’s version of the 2nd law. Sep 25, 2024. #5.
Calculating heat output from current - Physics Forums
2012年2月13日 · A few weeks ago I was talking to some mechanical and electrical engineers about combined heat and power. Combined heat and power, aka co-generation or co-gen, is generating electricity on site, usually by burning natural gas, and using the waste heat to heat your buildings, domestic hot water, or some other process.
How much power does my car actually need to maintain speed?
2015年3月15日 · It also touched on the losses in ICE/mechanical systems and the potential for recovering waste heat in hybrid setups. Overall, it was mentioned that most passenger cars only need about 20 hp to overcome rolling friction and air drag, and that there have been attempts to recover waste heat in car engines but with limited success.