How do you convert from joules to electron volts? | Socratic
2018年4月14日 · 1 eV = 1.60217662 ×10−19 J. 1 eV = 1.602 × 10−19 J, rounded to three decimal places. Conversely, one joule is the energy acquired by one coulomb of charge when it is accelerated through a potential difference of 1 volt. 1 J = (6.2415091× 1018 e) ×(1 V) 1 J = 6.2415091 ×1018 eV. 1 J = 6.242 × 1018 eV, rounded to three decimal places.
Cathode Ray Tube Experiment - Chemistry - Socratic
2014年4月22日 · Question #cd7c0. JJ Thompson did an experiment using a cathode ray tube and found that electrons passed from the surface of the cathode and accelerate toward the positively charged anode. The anode absorbed many electrons, but is the anode has slits some electrons will pass through. He is credited with the first discovery of the electron.
Planck's constant - Chemistry - Socratic
Planck's constant is h ≈ 6.63⋅ 10−34 J ⋅ s. This is one of the smallest constants in physics, and gives the relationship between a photon's energy and its frequency. Planck's constant is denoted h and is 6.26 x 10 (^ -34) J x s where J is Joules and s is seconds. It can be used to relate the energy of a photon (E) and the frequency of ...
How do you calculate the number of photons? + Example - Socratic
2014年8月22日 · EXAMPLE. A common laser pointer produces 1.0 mW at a wavelength of 670 nm. Calculate the number of photons produced per millisecond. Solution. Step 1. Calculate the energy of a photon. E = hc λ = 6.626 × 1034J⋅s ×2.998 × 108m⋅s−1 670 × 10−9m = 2.965 ×10−19J. ( 3 significant figures + 1 guard digit) Step 2.
What is the difference between the Rydberg constants
For a comparison of ~~109677 and 109737.32 "cm"^(-1), see this answer I gave earlier today. As for R_H = 109678.77174307_(10) "cm"^(-1) and R_(H) = 2.1787xx10^(-18) "J" (Inorganic Chemistry, Miessler et al.), clearly, the difference is in the units. We have reciprocal distance vs. energy. These do NOT have equivalent meanings, but they DO interconvert! The only difference in their usage, which ...
An electron changes from an n = 2 to an n = 6 energy state
2017年11月27日 · 4.85 * 10^(-19) "J" The question wants you to determine the energy that the incoming photon must have in order to allow the electron that absorbs it to jump from n_i = 2 to n_f = 6. A good starting point here will be to calculate the energy of the photon emitted when the electron falls from n_i = 6 to n_f = 2 by using the Rydberg equation. 1/(lamda) = R * (1/n_f^2 - 1/n_i^2) Here lamda si the ...
How can I calculate the wavelength from energy? - Socratic
2014年7月11日 · Wavelength from energy. The formula is. E = hc λ or λ = hc E, where h is Planck's constant. For example, what is the wavelength of a photon that has an energy of. 3.36 × 10⁻¹⁹ J? λ = hc E = 6.626 ×10⁻³⁴J⋅s ×2.998 × 10⁸m⋅s⁻¹ 3.36 × 10⁻¹⁹J = 5.91 × 10⁻⁷ m =. 591 nm. Answer link. To calculate the wavelength ...
How do you calculate the ionization energy (in kJ/mol) of
2016年8月18日 · To find the energy required to ionise a mole of ions you need to multiply by The Avogadro Constant which is [Math Processing Error]. [Math Processing Error] You can do it like this: You are given the expression for the energy of the electron: sf (E_n=- (2.18xx10^ (-18))Z^2 [1/n^2]) When the electron is in its ground state, the value of the ...
Can you go over q = m * c * DeltaT ? + Example - Socratic
2014年9月8日 · The specific heat capacity, or simply specific heat (C) of a substance is the amount of heat energy required to raise the temperature of one gram of the substance by one degree Celsius. Heat energy is usually measured in Joules ("J") or calories ("cal"). The variables in the equation q = mCDeltaT mean the following: " let:" q="heat energy gained or lost by a substance" m="mass (grams)" C ...
Specific Heat - Chemistry - Socratic
Specific heat represents the amount of heat required to change a unit mass of a substance by one degree Celsius. This is expressed mathematically as: DeltaT - the change in temperature. c = q/ (m * DeltaT). Since heat is measured in Joules (J), mass in grams (g), and temperature in degree Celsius (C), we can determine that. c = J/ (g * ^@C).